b^2-5b=18/2b

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Solution for b^2-5b=18/2b equation: 


b in (-oo:+oo)

b^2-(5*b) = (18/2)*b // - (18/2)*b

b^2-(5*b)-((18/2)*b) = 0

b^2-5*b-9*b = 0

b^2-14*b = 0

DELTA = (-14)^2-(0*1*4)

DELTA = 196

DELTA > 0

b = (196^(1/2)+14)/(1*2) or b = (14-196^(1/2))/(1*2)

b = 14 or b = 0

b in { 0, 14 }

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